[geeks] hrm, possible?

[Joshua D. Boyd]

Perl would take care of that for you.  Parse out the IP, and see if it is
in an associative array.  If not, add it.  If so, you've got a duplicate
session, so log to a file.

--
Joshua Boyd

On Fri, 29 Jun 2001, Bill Bradford wrote:

> Given an output like this:
> 
> bash-2.02# ps -fe |grep ovw |grep display
>  mbarnes 20452     1  0 11:05:34 ?        0:09 /opt/OV/bin/ovw -rw -display 172.17.8.151:0
> dtrujill 20078     1  0 09:33:27 ?        0:17 /opt/OV/bin/ovw -ro -display 172.17.11.241:0
> lwilliam 20473     1  0 11:10:53 ?        0:10 /opt/OV/bin/ovw -ro -display 172.17.9.166:0
> ojanuari 20432     1  0 11:00:44 ?        0:10 /opt/OV/bin/ovw -ro -display 172.17.11.135:0
>  dher405 20049     1  0 09:29:07 ?        0:11 /opt/OV/bin/ovw/ -ro -display 172.17.11.136:0
>   jwells 20139     1  0 09:47:17 ?        0:19 /opt/OV/bin/ovw -ro -display 172.17.8.206:0
>  mbarnes 20029     1 45 09:28:10 ?       11:31 /opt/OV/bin/ovw -rw -display 172.17.8.151:0
>  kfuk855 20368     1  0 10:45:05 ?        0:08 /opt/OV/bin/ovw -rw -display 172.17.10.135:0
>   proman 20509     1  1 11:31:38 ?        0:09 /opt/OV/bin/ovw -ro -display 172.17.11.64:0
> 
> Anybody know if it would be possible to write a script (in whatever
> language necessary) that would detect the duplicate sessions (note
> processes 20432 and 20368, pointing to the same IP address)?  I'm
> working on some way to detect when one of our lusers forgets to 
> kill his session before the next shift starts....
> 
> Bill (ugh! og programming rusty! og need sharp knife!)
> 
> -- 
> Bill Bradford
> mrbill at mrbill.net
> Austin, TX
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